Chemistry and Chemical Reactivity (9th Edition)

Published by Cengage Learning
ISBN 10: 1133949649
ISBN 13: 978-1-13394-964-0

Chapter 4 Stoichiometry: Quantitative Information about Chemical Reactions - Study Questions - Page 179f: 76


$0.500\ g$

Work Step by Step

Number of moles of $Br_2$: $0.102\ M\times 27.85\ mL=2.84\ mmol$ From stoichiometry: $2.84\ mmol$ of vitamin C $0.00284\ mol\times 176.13\ g/mol=0.500\ g$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.