Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 5 - Sections 5.1-5.10 - Exercises - Problems by Topic - Page 239: 48

Answer

$23.2psi$

Work Step by Step

We know that $PV=nRT$ But $n=\frac{m}{M}$ Where $m$ and $M$ are given mass and molar mass respectively $\implies PV=\frac{mRT}{M}$ This can be rearranged as $P=\frac{mRT}{VM}$ We plug in the known values to obtain: $P=\frac{16.0\times 0.08206\times 298}{3.45\times 44.0095}=2.5769atm$ Now we convert pressure from atm to psi $P=2.5769atim\times \frac{14.7psi}{1atm}=37.9psi$ Now we can find the gauge pressure as $37.9psi-14.7psi=23.2psi$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.