Answer
$V_2=4.22L$
Work Step by Step
According to Avogadro's law
$\frac{V_1}{n_1}=\frac{V_2}{n_2}$
This can be rearranged as
$V_2=\frac{V_1n_2}{n_1}$.......eq(1)
$n_2=0.158+0.113=0.271 mol$
We plug in the known values in eq(1) to obtain:
$V_2=\frac{2.46\times 0.271}{0.158}=4.22L$
