Answer
$V_2=47.5L$
Work Step by Step
We know that
$\frac{P_1V_1}{T_1}=\frac{P_2V_2}{T_2}$
This can be rearranged as
$V_2=\frac{P_1V_1T_2}{P_2T_1}$.........eq(1)
$T_1=28.0+273.15=301.15K$
$T_2=-15.0+273.15=258.15K$
We plug in the known values in eq(1) to obtain:
$V_2=\frac{748\times 28.5\times 258.15}{385\times 301.15}=47.5L$
