Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 5 - Sections 5.1-5.10 - Exercises - Problems by Topic - Page 239: 42

Answer

$T=360 K$

Work Step by Step

We know that $PV=nRT$ This can be rearranged as $T=\frac{PV}{nR}$ We plug in the known values to obtain: $T=\frac{1.3\times 11.8}{0.52\times 0.08206}$ $T=360 K$
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