Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 5 - Sections 5.1-5.10 - Exercises - Problems by Topic - Page 239: 45

Answer

$V=16.2L$

Work Step by Step

We know that $PV=nRT$ but $n=\frac{m}{M}$ Where $m$ and $M$ are given mass and molar mass respectively $\implies PV=\frac{mRT}{M}$ This can be rearranged as $V=\frac{mRT}{PM}$............eq(1) $P=742 mmHg\times\frac{1atm}{760mmHg}=0.97632atm$ We plug in the known values in eq(1) to obtain: $V=\frac{28.8\times 0.08206\times 295.15}{0.97632\times 44.0095}=16.2L$
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