Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 5 - Sections 5.1-5.10 - Exercises - Problems by Topic - Page 239: 41

Answer

$n=2.1 mol$

Work Step by Step

We know that $PV=nRT$ This can be rearranged as $n=\frac{PV}{RT}$ We plug in the known values to obtain: $n=\frac{1.8\times 28.5}{0.08206\times 298}=2.1 mol$
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