Answer
$V_2=420mL$
Work Step by Step
According to Avogadro's law
$\frac{V_1}{n_1}=\frac{V_2}{n_2}$
This can be rearranged as
$V_2=\frac{V_1n_2}{n_1}$.......eq(1)
$n_2=0.553+0.364=0.918 mol$
We plug in the known values in eq(1) to obtain:
$V_2=\frac{253\times 0.918}{0.553}=420mL$