Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 131: 53c


The formula of sulfurous acid is $H_{2}SO_{3}$.

Work Step by Step

Oxyacids with oxanions ending in -ite are named as : $ 'base name \hspace{1mm}of \hspace{1mm}oxyanion' + ous + acid$ Here, $sulfur$ is the basename and the oxyanion ends in $-ite$. so, the oxyanion is sulfite: $SO_{3}^{2-}$. To balance the charges, 2 hydrogen ions are present. So, the formula of sulfurous acid is $H_{2}SO_{3}$.
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