Answer
Copper (II) Chloride - CuCl$_{2}$
Work Step by Step
1. First Identify that Coper (II) Chloride is an ionic compound.
2. Then, write the formula for the first element (Cu)
Note: We are told that Copper has a charge of 2$^{+}$
3. Then write the name of the second element (Cl)
4. Cross down the charges of both of the elements to get CuCl$_{2}$