Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 131: 35c


Final compound formed has the formula $Ca_{3}(PO_{4})_{2}$.

Work Step by Step

The metal cation is $Ca^{2+}$ The polyatomic anion is $PO_{4}^{3-}$ Combine 3 $Ca^{2+}$ and 2 $PO_{4}^{3-}$ to balance the charge. Final compound formed has the formula $Ca_{3}(PO_{4})_{2}$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.