Chemistry: A Molecular Approach (3rd Edition)

Published by Prentice Hall
ISBN 10: 0321809246
ISBN 13: 978-0-32180-924-7

Chapter 3 - Sections 3.1-3.12 - Exercises - Problems by Topic - Page 131: 35b


Final compound formed has the formula $CaCrO_{4}$.

Work Step by Step

The metal cation is $Ca^{2+}$ The polyatomic anion is $CrO_{4}^{2-}$ Combine 1 $Ca^{2+}$ and 1 $CrO_{4}^{2-}$ to balance the charge. Final compound formed has the formula $CaCrO_{4}$.
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