Answer
Final compound formed has the formula $CaCrO_{4}$.
Work Step by Step
The metal cation is $Ca^{2+}$
The polyatomic anion is $CrO_{4}^{2-}$
Combine 1 $Ca^{2+}$ and 1 $CrO_{4}^{2-}$ to balance the charge.
Final compound formed has the formula $CaCrO_{4}$.
