## Chemistry: A Molecular Approach (3rd Edition)

Iron (II) Phosphate - $Fe_{3}(PO_{4})_{2}$
1. To begin, write the name of the first element with its charge. (We are told that Iron has a charge of 2+ as indicated by the "(II)") Fe$^{2+}$ 2. Then write the name of the second element with its charge. (Note - Phosphate is a poly-atomic ion so, you have to remember its charge.) PO$_{4}^{3-}$ 3. Cross down the charges on both of the elements (+2 and -3) to get: $$Fe_{3}(PO_{4})_{2}$$