Answer
lead (II) Chromate - $PbCrO_{4}$
Work Step by Step
1. To begin, write the name of the first element with its charge. (We are told that Lead has a charge of 2). Pb$^{2+}$
2. Then write the name of the second element with its charge. (Note - Chromate is a poly-atomic ion so, you have to remember its charge.) CrO$_{4}^{2-}$
3. Cross down the charges on both of the elements (+2 and -2) to get:
$$PbCrO_{4}$$
