Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 18 - Electrochemistry - Questions & Problems - Page 850: 18.22

Answer

The one with a positive $E^{\circ}{cell}$ value proceeds towards the formation of more products at equilibrium.

Work Step by Step

The one with a positive $E^{\circ}{cell}$ value proceeds towards the formation of more products at equilibrium. We have a relation connecting $ \Delta G^{\circ}$ and $E^{\circ}{cell}$. $ \Delta G^{\circ}= -n FE^{\circ}{cell}$ Where $ \Delta G^{\circ} = standard\ free\ energy\ change$ n = number of electrons involved in cell reaction. F = Faraday’s constant $E^{\circ}{cell}= Standard cell EMF $ So if we substitute a negative $E^{\circ}{cell}$ value in the above equation, $ \Delta G^{\circ}$ becomes positive which means the reaction is non-spontaneous. On the other hand, if we substitute a positive $E^{\circ}{cell}$ value in the above equation, $ \Delta G^{\circ}$ becomes negative which means the reaction is spontaneous and products will form.
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