Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 18 - Electrochemistry - Questions & Problems - Page 850: 18.21

Answer

$ K =e^{RT\div nFE^{\circ}cell} $

Work Step by Step

$ \Delta G^{\circ} =-nFE^{\circ}cell$ Equation (1) Where, $ \Delta G^{\circ} = standard\ free\ energy\ change $ n= number of electrons involved in the cell reaction F = Faraday's constant $ E^{\circ}{cell} $ = Standard cell EMF $ \Delta G^{\circ} =-RT lnK$ Equation (2) R = Universal gas constant T = Absolute temparature K = Equilibrim constant of the cell reaction Combining equation (1) and (2) we have $ -nFE^{\circ}cell =-RT lnK$ $lnK =RT\div nFE^{\circ}cell$ Taking exponentials on both sides we have $ K =e^{RT\div nFE^{\circ}cell} $
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