Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 18 - Electrochemistry - Questions & Problems - Page 850: 18.18

Answer

The better reducing agents are Li $ H_{2(g)}$ $ Fe^{2+}(aq)$ $ Co^{2+}(aq)$

Work Step by Step

The better reducing agents are ones with lower standard reduction potential values. $Na^{+}(aq)/Na$(-2.71 V) and $Li^{+}(aq)/Li$(-3.05 V) From the above values, the Li with lower reduction potential (higher negative value) is a better reducing agent. Comparing $ H^{+}/H_{2(g)}$ [0.00 V] and $ I_{2(g)}/I^{-}$ [+0.53 V], $ H_{2(g)}$ is a better reducing agent. Comparing $ Fe^{2+}(aq)/Fe_{(s)}$ [-0.44 V] and $ Ag^{+}(aq)/Ag_{(s)} $[ +0.80 V], $ Fe^{2+}(aq) $ is a better reducing agent. Comparing $ Br_{2(g)}/Br^{-}$ [+1.07 V] and $ Co^{2+}(aq)/Co_{(s)}$ [-0.28 V], $ Co^{2+}(aq)$ is a better reducing agent.
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