Answer
$Fe^{3+}$ can oxidize $I^{-}$ to $I_{2}$ under standard-state conditions.
Work Step by Step
$E^{\circ}_{Fe^{3+}/Fe}=0.77\,V$
$E^{\circ}_{I_{2}/I^{-}}=0.53\,V$
Since $E^{\circ}_{Fe^{3+}/Fe}$ is more positive than $E^{\circ}_{I_{2}/I^{-}}$, $Fe^{3+}$ will have more tendency to get reduced or to oxidise $I^{-}$ to $I_{2}$.
$Fe^{3+}$ can oxidize $I^{-}$ to $I_{2}$ under standard-state conditions.
