## Chemistry 12th Edition

(a) $CH_2ClCOO^-$ (b) $IO_4^-$ (c) $H_2PO_4^-$ (d) $HPO_4^{2-}$ (e) $PO_4^{3-}$ (f) $HSO_4^-$ (g) $SO_4^{2-}$ (h) $IO_3^-$ (i) $SO_3^{2-}$ (j) $NH_3$ (k) $HS^-$ (l) $S^{2-}$ (m) $ClO^-$
The conjugate base of an acid is, basically, the acid when a $(H^+)$ is removed. Therefore, we should follow these steps: 1. Remove a Hydrogen from the compound. 2. Subtract 1 from its charge.