Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 15 - Acids and Bases - Questions & Problems: 15.8

Answer

(a) $CH_2ClCOO^-$ (b) $IO_4^-$ (c) $H_2PO_4^-$ (d) $HPO_4^{2-}$ (e) $PO_4^{3-}$ (f) $HSO_4^-$ (g) $SO_4^{2-}$ (h) $IO_3^-$ (i) $SO_3^{2-}$ (j) $NH_3$ (k) $HS^-$ (l) $S^{2-}$ (m) $ClO^-$

Work Step by Step

The conjugate base of an acid is, basically, the acid when a $(H^+)$ is removed. Therefore, we should follow these steps: 1. Remove a Hydrogen from the compound. 2. Subtract 1 from its charge.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.