## Chemistry 12th Edition

(a) = $3.80 \times 10^{-3}$ (b) = $6.17 \times 10^{-12}$ (c) = $1.10 \times 10^{-7}$ (d) = $1.00 \times 10^{-15}$
Use the equation: $[H^+] = 10^{-pH}$ To find the concentrations. (a) $[H^+] = 10^{-2.42} = 3.80 \times 10^{-3}$ (b) $[H^+] = 10^{-11.21} = 6.17 \times 10^{-12}$ (c) $[H^+] = 10^{-6.96} = 1.10 \times 10^{-7}$ (d) $[H^+] = 10^{-15} = 1 \times 10^{-15}$