Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 15 - Acids and Bases - Questions & Problems - Page 710: 15.15


Please see the work below.

Work Step by Step

We are given that $[HCl]=1.4\times 10^{-3}M$ We know that $[H^+]\times [OH^-]=1\times 10^{-14}$ Thus $OH^-=\frac{1\times 10^{-14}}{H^+}=\frac{1\times 10^{-14}}{1.4\times 10^{-3}}=7.14\times 10^{-10}$
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