## Chemistry 12th Edition

pOH is the negative logarithm of the $OH^-$ concentration ($M$). $pOH = -log[OH^-]$ The equation that relates pOH and pH is: $pH + pOH = 14$
This equation is the derivation of the $K_w$ equation: $[H^+] \times [OH^-] = 10^{-14}$ $log ([H^+] \times [OH^-]) = log(10^{-14})$ $log[H^+] + log[OH^-] = -14$ $-pH + (-pOH) = -14$ $pH + pOH = 14$