## Chemistry 12th Edition

$2.18 \times 10^{-3}$ grams.
1. Find the concentration of $[OH^-]$: $pOH + pH = 14$ $pOH + 10 = 14$ $pOH = 4$ $[OH^-] = 10^{-pOH} = 10^{-4}$ 2. Since $NaOH$ is a strong base: $[NaOH] = [OH^-] = 10^{-4}$ 3. With the concentration and the volume, find the number of moles: $546 ml = 0.546L$ $n(moles) = concentration(M) \times volume(L)$ $n(moles) = 10^{-4} \times 0.546 = 5.46 \times 10^{-5}$ 4. Find the molar mass of $NaOH$. Na: 23 O: 16 H: 1 NaOH = 40 g/mol. 5. Find the mass of $5.46 \times 10^{-5}$ moles of $NaOH$. $mass(g) = n(moles) \times molar mass$ $mass(g) = 5.46 \times 10^{-5} \times 40 = 2.18 \times 10^{-3}g$