Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 15 - Acids and Bases - Questions & Problems: 15.25

Answer

$ 2.18 \times 10^{-3}$ grams.

Work Step by Step

1. Find the concentration of $[OH^-]$: $pOH + pH = 14$ $pOH + 10 = 14$ $pOH = 4$ $[OH^-] = 10^{-pOH} = 10^{-4}$ 2. Since $NaOH$ is a strong base: $[NaOH] = [OH^-] = 10^{-4}$ 3. With the concentration and the volume, find the number of moles: $546 ml = 0.546L$ $n(moles) = concentration(M) \times volume(L)$ $n(moles) = 10^{-4} \times 0.546 = 5.46 \times 10^{-5}$ 4. Find the molar mass of $NaOH$. Na: 23 O: 16 H: 1 NaOH = 40 g/mol. 5. Find the mass of $5.46 \times 10^{-5}$ moles of $NaOH$. $mass(g) = n(moles) \times molar mass$ $mass(g) = 5.46 \times 10^{-5} \times 40 = 2.18 \times 10^{-3}g$
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