Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 15 - Acids and Bases - Questions & Problems: 15.17

Answer

(a) $pH = 3.0$ (b) $pH = 13.9$

Work Step by Step

(a) 1. HCl is a strong acid, therefore: $[HCl] = [H^+] = 0.0010M$ 2. Use the pH formula to find the pH value: $pH = -log[H^+]$ $pH = -log(0.0010)$ $pH = 3.0$ (b) 1. KOH is a strong base, therefore: $[KOH] = [OH^-] = 0.76M$ 2. Use the pOH formula to find the pOH: $pOH = -log[OH^-]$ $pOH = -log[0.76]$ $pOH = 0.12$ 3. Find the pH: $pH + pOH = 14.0$ $pH + 0.12 = 14.0$ $pH = 14.0 - 0.12$ $pH = 13.9$
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