## Chemistry 12th Edition

(a) $pH = 3.0$ (b) $pH = 13.9$
(a) 1. HCl is a strong acid, therefore: $[HCl] = [H^+] = 0.0010M$ 2. Use the pH formula to find the pH value: $pH = -log[H^+]$ $pH = -log(0.0010)$ $pH = 3.0$ (b) 1. KOH is a strong base, therefore: $[KOH] = [OH^-] = 0.76M$ 2. Use the pOH formula to find the pOH: $pOH = -log[OH^-]$ $pOH = -log[0.76]$ $pOH = 0.12$ 3. Find the pH: $pH + pOH = 14.0$ $pH + 0.12 = 14.0$ $pH = 14.0 - 0.12$ $pH = 13.9$