Answer
$-2\sqrt 3$
Work Step by Step
$-4\sin (3\times\frac{\pi}{6}+\frac{\pi}{6})=-4\sin(\frac{4\pi}{6})$
$=-4\sin(\frac{2\pi}{3})=-4\sin(\pi-\frac{\pi}{3})$
$=-4\sin\frac{\pi}{3}=-4\times\frac{\sqrt 3}{2}=-2\sqrt 3$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 78
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