Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 78


$-2\sqrt 3$

Work Step by Step

$-4\sin (3\times\frac{\pi}{6}+\frac{\pi}{6})=-4\sin(\frac{4\pi}{6})$ $=-4\sin(\frac{2\pi}{3})=-4\sin(\pi-\frac{\pi}{3})$ $=-4\sin\frac{\pi}{3}=-4\times\frac{\sqrt 3}{2}=-2\sqrt 3$
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