Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 66



Work Step by Step

$\dfrac{\pi}{6}$ is a special angle whose cosine value is $\dfrac{\sqrt3}{2}$. Thus, $-\cos{(\frac{\pi}{6})}=-(\cos{(\frac{\pi}{6})}) = -\dfrac{\sqrt3}{2}$
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