Answer
$-\dfrac{\sqrt3}{2}$
Work Step by Step
$\dfrac{\pi}{6}$ is a special angle whose cosine value is $\dfrac{\sqrt3}{2}$.
Thus,
$-\cos{(\frac{\pi}{6})}=-(\cos{(\frac{\pi}{6})}) = -\dfrac{\sqrt3}{2}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 66
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