Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 69

Answer

$\dfrac{\sqrt3}{2}$

Work Step by Step

Substitute $\frac{\pi}{6}$ to $x$ to obtain: $\sin{(2x)}= \sin{2(\frac{\pi}{6})}=\sin{(\frac{\pi}{3})}$ $\dfrac{\pi}{3}$ is a special angle whose sine value is $\dfrac{\sqrt{3}}{2}$. Thus, when $x=\frac{\pi}{6}$, $\sin{(2x)} = \dfrac{\sqrt3}{2}$
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