## Trigonometry 7th Edition

$\frac{\sqrt 3}{2}$
We know, $\sin(\frac{\pi}{2}+x)$ = $\cos x$ Given that x = $\frac{\pi}{6}$ Then, $\sin(\frac{\pi}{6}+\frac{\pi}{2})$ = $\cos \frac{\pi}{6}$ = $\frac{\sqrt 3}{2}$