Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 60

Answer

$\dfrac{\sqrt{3}}{3}$

Work Step by Step

$\dfrac{\pi}{3}$ is a special angle whose tangent value is $\sqrt3$. (Please refer to Table 1 on page 128 of this book). Since cotangent is the reciprocal of tangent, then $\cot{(\frac{\pi}{3})}=\dfrac{1}{\tan{(\frac{\pi}{3})}}=\dfrac{1}{\sqrt{3}} =\dfrac{1}{\sqrt{3}} \cdot \dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt{3}}{3}$
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