## Trigonometry 7th Edition

$\dfrac{\sqrt{3}}{3}$
$\dfrac{\pi}{3}$ is a special angle whose tangent value is $\sqrt3$. (Please refer to Table 1 on page 128 of this book). Since cotangent is the reciprocal of tangent, then $\cot{(\frac{\pi}{3})}=\dfrac{1}{\tan{(\frac{\pi}{3})}}=\dfrac{1}{\sqrt{3}} =\dfrac{1}{\sqrt{3}} \cdot \dfrac{\sqrt3}{\sqrt3}=\dfrac{\sqrt{3}}{3}$