Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 76



Work Step by Step

$\sin(\frac{\pi}{6}-\frac{\pi}{3})$ = $\sin(\frac{-3\pi}{18}) = \sin(-\frac{\pi}{6})$ Using the identity $\sin(-x) = -\sin x$ we obtain, $\sin(-\frac{\pi}{6})$ = $-\sin\frac{\pi}{6}$ = $-\frac{1}{2}$
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