Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 3 - Section 3.2 - Radians and Degrees - 3.2 Problem Set - Page 133: 74



Work Step by Step

Substitute $\frac{\pi}{6}$ to $x$ to obtain: $2+\cos{x}= 2+\cos{(\frac{\pi}{6})}$ $\dfrac{\pi}{6}$ is a special angle whose cosine value is $\dfrac{\sqrt3}{2}$. Thus, when $x=\frac{\pi}{6}$, $2+\cos{x} = 2+ \dfrac{\sqrt3}{2}=\dfrac{4}{2} + \dfrac{\sqrt3}{2} = \dfrac{4+\sqrt3}{2}$
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