Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 249: 66


$2~cos^2~\frac{x}{2}~tan~x = tan~x+sin~x$

Work Step by Step

$2~cos^2~\frac{x}{2}~tan~x = 2~(\sqrt{\frac{1+cos~x}{2}})^2~tan~x$ $2~cos^2~\frac{x}{2}~tan~x = 2~(\frac{1+cos~x}{2})~tan~x$ $2~cos^2~\frac{x}{2}~tan~x = (1+cos~x)~tan~x$ $2~cos^2~\frac{x}{2}~tan~x = tan~x+cos~x~tan~x$ $2~cos^2~\frac{x}{2}~tan~x = tan~x+cos~x~\frac{sin~x}{cos~x}$ $2~cos^2~\frac{x}{2}~tan~x = tan~x+sin~x$
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