Trigonometry (11th Edition) Clone

$\frac{1-cos~2x}{sin~2x} = tan~x$
$\frac{1-cos~2x}{sin~2x}$ When we graph this function, it looks like the graph of $~~tan~x$ We can verify this algebraically: $\frac{1-cos~2x}{sin~2x}$ $= \frac{1-(1-2~sin^2~x)}{2~sin~x~cos~x}$ $= \frac{2~sin^2~x}{2~sin~x~cos~x}$ $= \frac{sin~x}{cos~x}$ $= tan~x$