Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 249: 40


$sin~y = \sqrt{\frac{2}{3}}$

Work Step by Step

If $\frac{\pi}{2} \lt y \lt \pi$, then the angle $y$ is in quadrant II. We can find the value of $sin~y$: $sin~y = \sqrt{\frac{1-cos~2y}{2}}$ $sin~y = \sqrt{\frac{1-(-\frac{1}{3})}{2}}$ $sin~y = \sqrt{\frac{(\frac{4}{3})}{2}}$ $sin~y = \sqrt{\frac{2}{3}}$
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