Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 249: 45


$\frac{sin~x}{1-cos~x} = cot~\frac{x}{2}$

Work Step by Step

$\frac{sin~x}{1-cos~x}$ When we graph this function, it looks like the graph of $~~cot~\frac{x}{2}$ We can verify this algebraically: $\frac{sin~x}{1-cos~x}$ $=\frac{1}{\frac{1-cos~x}{sin~x}}$ $=\frac{1}{tan~\frac{x}{2}}$ $=cot~\frac{x}{2}$
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