Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 249: 48


$csc~x-cot~x = tan~\frac{x}{2}$

Work Step by Step

$csc~x-cot~x$ When we graph this function, it looks like the graph of $~~tan~\frac{x}{2}$ We can verify this algebraically: $csc~x-cot~x$ $=\frac{1}{sin~x}-\frac{cos~x}{sin~x}$ $=\frac{1-cos~x}{sin~x}$ $=tan~\frac{x}{2}$
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