Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 249: 42


$sin~2x = -0.96$

Work Step by Step

If $\frac{\pi}{2} \lt x \lt \pi$, then the angle $x$ is in quadrant II. If $sin~x = 0.6$, then $cos~x = -\sqrt{1-sin^2~x} = -0.8$ We can find the value of $sin~2x$: $sin~2x = 2~sin~x~cos~x$ $sin~2x = (2)(0.6)(-0.8)$ $sin~2x = -0.96$
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