Answer
$sin~2x = -0.96$
Work Step by Step
If $\frac{\pi}{2} \lt x \lt \pi$, then the angle $x$ is in quadrant II.
If $sin~x = 0.6$, then $cos~x = -\sqrt{1-sin^2~x} = -0.8$
We can find the value of $sin~2x$:
$sin~2x = 2~sin~x~cos~x$
$sin~2x = (2)(0.6)(-0.8)$
$sin~2x = -0.96$
