Trigonometry (11th Edition) Clone

Published by Pearson
ISBN 10: 978-0-13-421743-7
ISBN 13: 978-0-13421-743-7

Chapter 5 - Review Exercises - Page 249: 52

Answer

$\frac{sin~2x}{sin~x} = \frac{2}{sec~x}$

Work Step by Step

$\frac{sin~2x}{sin~x} = \frac{2~sin~x~cos~x}{sin~x}$ $\frac{sin~2x}{sin~x} = \frac{2~cos~x}{1}$ $\frac{sin~2x}{sin~x} = \frac{2}{\frac{1}{cos~x}}$ $\frac{sin~2x}{sin~x} = \frac{2}{sec~x}$
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