Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.1 - Vectors in Two Dimensions - 9.1 Exercises - Page 637: 34

Answer

$2\vec{u}=2\vec{i}$ $-3\vec{v}=6\vec{j}$ $\vec{u}+\vec{v}=\vec{i}-2\vec{j}$ $3\vec{u}-4\vec{v}=3\vec{i}+8\vec{j}$

Work Step by Step

$\vec{u}=\vec{i},$ $\vec{v}=-2\vec{j}$ $2\vec{u}$ Multiply both components of the vector $\vec{u}$ by $2$: $2\vec{u}=2\vec{i}$ $-3\vec{v}$ Multiply both components of the vector $\vec{v}$ by $-3$: $-3\vec{v}=-3(-2\vec{j})=6\vec{j}$ $\vec{u}+\vec{v}$ Add the same component from both vectors together and simplify: $\vec{u}+\vec{v}=\vec{i}-2\vec{j}$ $3\vec{u}-4\vec{v}$ Multiply $\vec{u}$ by $3$ and $\vec{v}$ by $-4$, then add the two vectors together and simplify: $3\vec{u}-4\vec{v}=3\vec{i}-4(-2\vec{j})=3\vec{i}+8\vec{j}$
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