Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 9 - Section 9.1 - Vectors in Two Dimensions - 9.1 Exercises - Page 637: 33

Answer

$2\vec{u}=\langle0,-2\rangle$ $-3\vec{v}=\langle6,0\rangle$ $\vec{u}+\vec{v}=\langle-2,-1\rangle$ $3\vec{u}-4\vec{v}=\langle8,-3\rangle$

Work Step by Step

$\vec{u}=\langle0,-1\rangle,$ $\vec{v}=\langle-2,0\rangle$ $2\vec{u}$ Multiply both components of the vector $\vec{u}$ by $2$: $2\vec{u}=2\langle0,-1\rangle=\langle0,-2\rangle$ $-3\vec{v}$ Multiply both components of the vector $\vec{v}$ by $-3$: $-3\vec{v}=-3\langle-2,0\rangle=\langle6,0\rangle$ $\vec{u}+\vec{v}$ Add the same component from both vectors together and simplify: $\vec{u}+\vec{v}=\langle0,-1\rangle+\langle-2,0\rangle=\langle0-2,-1+0\rangle=\langle-2,-1\rangle$ $3\vec{u}-4\vec{v}$ Multiply the vector $\vec{u}$ by $3$ and the vector $\vec{v}$ by $-4$, then add them together and simplify: $3\vec{u}-4\vec{v}=3\langle0,-1\rangle-4\langle-2,0\rangle=\langle0,-3\rangle+\langle8,0\rangle=...$ $...=\langle8,-3\rangle$
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