Answer
terminal point:$ \quad(3,5)$
Work Step by Step
If the initial point of a vector $< u_{1},u_{2} >$ is $(x_{0},y_{0}),$
then the terminal point is $(x_{0}+u_{1},y_{0}+u_{2})$
Here, given the initial point $(x_{0},y_{0})=(4,3)$
and $< u_{1},u_{2} > = < -1,2 >$
the terminal point is
$(4-1,3+2)=(3,5)$