Answer
terminal point:$ \quad(-4,2)$
Work Step by Step
If the initial point of a vector $< u_{1},u_{2} >$ is $(x_{0},y_{0}),$
then the terminal point is $(x_{0}+u_{1},y_{0}+u_{2})$
Here, given the initial point $(x_{0},y_{0})=(4,3)$
and $< u_{1},u_{2} > = < -8,-1 >$
the terminal point is
$(4-8,3-1)=(-4,2)$