Answer
$72.5^\circ$, $19ft$
Work Step by Step
As shown in the figure, $cos(t)=\frac{6}{20}=0.3$ and we can find that
$t=cos^{-1}(0.3)\approx72.5^\circ$ and $h=\sqrt {20^2-6^2}=19ft$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 6 - Section 6.4 - Inverse Trigonometric Functions and Right Triangles - 6.4 Exercises - Page 507: 39
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