Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 6 - Section 6.4 - Inverse Trigonometric Functions and Right Triangles - 6.4 Exercises - Page 507: 22

Answer

$27.3^\circ$

Work Step by Step

From given triangle- $\cos\theta$ = $\frac{8}{9}$ Therefore- $\theta$ = $\cos^{-1} \frac{8}{9}$ Using calculator in degree mode- $\cos^{-1}$ → $8\div9$ = 27.2660444507 i.e. $\theta$ = $\cos^{-1}(\frac{8}{9}) \approx 27.3^\circ$ (Rounded to one decimal place)
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