Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.4 - Laws of Logarithms - 4.4 exercises - Page 359: 66

Answer

0.368743

Work Step by Step

$Use$ $the$ $Change$ $of$ $Base$ $Formula$ $and$ $a$ $calculator$ $to$ $evaluate$ $the$ $logarithm$: $\log_{12} 2.5$ Apply the Change of Base Formula: $\log_x y$ = $\frac{\log y}{\log x}$ $\log_{12} 2.5$ = $\frac{\log 2.5}{\log 12}$ Use a calculator and round to the sixth decimal place $\approx$0.368743
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