Answer
$\log x$ - $\frac{1}{3}$$\log (1-x)$
Work Step by Step
$Expand$ $the$ $expression$:
$\log (\frac{x}{\sqrt[3]{1-x}})$
Apply the Second Law of Logarithms
$\log (\frac{x}{\sqrt[3]{1-x}})$ = $\log x$ - $\log \sqrt[3]{1-x}$
Rewrite the cube root
$\log x$ - $\log (1-x)^\frac{1}{3}$
Apply the Third Law of Logarithms for $\log (1-x)^\frac{1}{3}$
$\log (1-x)^\frac{1}{3}$ = $\frac{1}{3}$$\log (1-x)$
$\log x$ - $\frac{1}{3}$$\log (1-x)$
