Answer
$\log_3 2$ +$\log_3 x$ - $\log_3 y$
Work Step by Step
$Expand$ $the$ $expression$:
$\log_3 \frac{2x}{y}$
Apply the Third Law of Logarithms
$\log_3 \frac{2x}{y}$ = $\log_3 2x$ - $\log_3 y$
Apply the First Law of Logarithms to $\log_3 2x$
$\log_3 (2\times x )$ = $\log_3 2$ +$\log_3 x$
$\log_3 2x$ - $\log_3 y$ = $\log_3 2$ +$\log_3 x$ - $\log_3 y$
