Answer
$\log_a (\frac{bd^c}{s^r})$
Work Step by Step
$Combine$ $the$ $expresssion$:
$\log_a b$ + $c$$\log_a d$ - $r$$\log_a s$
Apply the Third Law of Logarithms for $c$$\log_a d$ and $r$$\log_a s$
$c$$\log_a d$ = $\log_a d^c$
$r$$\log_a s$ = $\log_a s^r$
$\log_a b$ + $\log_a d^c$ - $\log_a s^r$
Apply the First Law of Logarithms for $\log_a b$ + $\log_a d^c$
$\log_a b$ + $\log_a d^c$ = $\log_a (b\times d^c)$
$\log_a (bd^c)$ - $\log_a s^r$
Apply the Second Law of Logarithms
$\log_a (bd^c)$ - $\log_a s^r$ = $\log_a (\frac{bd^c}{s^r})$
