Answer
3
Work Step by Step
$\log_2 6$ - $\log_2 15$ + $\log_2 20$
We can bring together $\log_2 6$ + $\log_2 20$ using the First Law of Logarithms
$\log_2 (6 \times 20)$ - $\log_2 15$
Apply the Second Law of Logarithms
$\log_2 \frac{120}{15}$
$\log_2 8$
$\log_2 2^3$ ($2^3$ = 2 $\times$ 2 $\times$ 2 = 8)
=3
