Answer
$\frac{1}{3}$$\log (x^2+4)$
Work Step by Step
$Expand$ $the$ $expression$:
$\log \sqrt[3]{x^2+4}$
Rewrite the cube root
$\log (x^2+4)^\frac{1}{3}$
Apply the Third Law of Logarithms
$\log (x^2+4)^\frac{1}{3}$ = $\frac{1}{3}$$\log (x^2+4)$
No further expansion can take place
$\frac{1}{3}$$\log (x^2+4)$
