Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 4 - Section 4.4 - Laws of Logarithms - 4.4 exercises - Page 359: 42


$\frac{1}{3}$$\log (x^2+4)$

Work Step by Step

$Expand$ $the$ $expression$: $\log \sqrt[3]{x^2+4}$ Rewrite the cube root $\log (x^2+4)^\frac{1}{3}$ Apply the Third Law of Logarithms $\log (x^2+4)^\frac{1}{3}$ = $\frac{1}{3}$$\log (x^2+4)$ No further expansion can take place $\frac{1}{3}$$\log (x^2+4)$
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